KeyError: trying to access missing dictionary key

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The error message:

KeyError: 'missing_key'

occurs when you attempt to access a key in a dictionary that does not exist.


1. Common Causes and Fixes

Cause 1: Accessing a Non-Existent Key

If you try to retrieve a value using a key that is not present in the dictionary, Python raises a KeyError.

Incorrect Code:

data = {"name": "Alice", "age": 25}
print(data["city"]) # Error: 'city' key does not exist

Solution: Use .get() to return a default value instead of raising an error.

print(data.get("city", "Key not found"))  # Output: "Key not found"

Cause 2: Using a Key with a Typo or Case Difference

Dictionaries in Python are case-sensitive, meaning "Name" and "name" are different keys.

Incorrect Code:

data = {"Name": "Alice"}
print(data["name"]) # Error: 'name' is different from 'Name'

Solution: Normalize keys using .lower().strip().

key = " name ".strip().lower()
data = {"name": "Alice"} # Convert keys to lowercase
print(data.get(key, "Key not found")) # Output: Alice

Cause 3: Using pop() on a Missing Key

If you call .pop() on a key that doesn’t exist, Python raises a KeyError.

Incorrect Code:

data = {"name": "Alice"}
data.pop("age") # Error: 'age' key does not exist

Solution: Provide a default value to .pop().

data.pop("age", "Key not found")  # Output: "Key not found"

Cause 4: Iterating Over a List of Dictionaries Without Checking Keys

If you’re looping through a list of dictionaries and assume a key always exists, you may run into a KeyError.

Incorrect Code:

data = [{"name": "Alice"}, {"age": 25}]
for item in data:
print(item["name"]) # Error: The second dictionary has no 'name' key

Solution: Use .get() to prevent errors.

for item in data:
print(item.get("name", "Key not found"))

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