ResourceWarning: unclosed file

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The warning ResourceWarning: unclosed file occurs when a file is opened but not properly closed in Python. If a file is left unclosed, it may lead to memory leaks, locked files, or unexpected behavior in certain operating systems.


1. Why Does This Happen?

  • Forgetting to Close the File → Using open() without close().
  • Exceptions Prevent Closing → If an error occurs before file.close() is executed.
  • Garbage Collection Delay → In some Python versions, files are not closed immediately after use.

2. Common Causes and Solutions

Cause 1: Forgetting to Close the File

If you open a file but don’t close it manually, Python warns about an unclosed file.

Example (File Not Closed)

file = open("example.txt", "r")
data = file.read()
# Forgot to close the file!

Solution: Close the File After Use

file = open("example.txt", "r")
data = file.read()
file.close() # Manually closing the file

Cause 2: Not Using with open()

If an exception occurs before file.close(), the file remains unclosed.

Example (Error Before Closing)

file = open("example.txt", "r")
data = file.read()
raise Exception("Something went wrong!") # File won't be closed
file.close() # This won't execute

Solution: Use with open() (Auto-Closing Mechanism)
Using with open() ensures that Python automatically closes the file after exiting the block.

with open("example.txt", "r") as file:
data = file.read() # File closes automatically after the block
  • This is the best practice to prevent ResourceWarning.

Cause 3: Unclosed File in a Function

If a function opens a file and doesn’t close it, a ResourceWarning may appear.

Example (Function Doesn’t Close File)

def read_file():
file = open("example.txt", "r")
return file.read() # File remains open

print(read_file()) # Warning: unclosed file!

Solution: Use with open() in Functions

def read_file():
with open("example.txt", "r") as file:
return file.read() # File automatically closes

print(read_file()) # No warning

Cause 4: Delayed Garbage Collection

In some Python versions (e.g., Python 3.6+), files are not immediately closed when they go out of scope.

Example (Relying on Garbage Collection)

def open_file():
file = open("example.txt", "r")
return file.read() # File stays open in some cases

data = open_file()

Solution: Explicitly Close the File

def open_file():
with open("example.txt", "r") as file:
return file.read() # File is closed automatically

data = open_file()

Alternative: Manually Call Garbage Collection

import gc
gc.collect() # Forces Python to release unclosed files
  • This is useful only if third-party libraries leave files open.

Cause 5: Using Open Files in Iterators or Generators

If a generator function yields from an open file, it may not close the file.

Example (Generator Keeping File Open)

def read_lines():
file = open("example.txt", "r")
for line in file:
yield line # File stays open while iterating

gen = read_lines() # File is still open

Solution: Use with open() Inside the Generator

def read_lines():
with open("example.txt", "r") as file:
for line in file:
yield line # File closes automatically

gen = read_lines() # No warning

3. Summary of Fixes

IssueFix
Forgetting to close a fileUse file.close() or with open()
Errors before file.close()Use with open() to auto-close
Functions leaving files openUse with open() inside functions
Delayed garbage collectionManually call gc.collect()
Iterators keeping files openUse with open() inside generators

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